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Inessa05 [86]
2 years ago
7

Solve. −6 1/4x=−3 1/8 What is the solution to the equation? Enter your answer as a simplified fraction in the box.

Mathematics
1 answer:
tresset_1 [31]2 years ago
4 0
X would be equal to -0.5
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Sally has seventy dollars to spend on eight books. After buying them she had thirteen dollars. How much did each book cost?
Anit [1.1K]

Answer:

7.13 each

Step-by-step explanation:

70 - 13 = 57. Divide 57/8 and get your answer

(7.125 rounded is 7.13)

5 0
2 years ago
Read 2 more answers
In Exercise, describe how the graph of g is related to the graph of f.<br> g(x)=-1+f(x)
Jet001 [13]

Answer:

The graph of g is the graph of f shifted down 1 unit.

Step-by-step explanation:

Suppose you have a function y = f(x), you can do these following operations on the function:

Shift up a units: y = f(x) + a

Shift down a units: y = f(x) - a

Shift left a units: y = f(x + a)

Shift right a units: y = f(x - a)

In this problem, we have that:

g(x) = -1 + f(x) = f(x) - 1

So the graph of g is the graph of f shifted down 1 unit.

7 0
3 years ago
How do I solve number 10? I'm not sure if I did it right.
grandymaker [24]
No, you did it right
3 0
2 years ago
Determine whether (18+35)x4=18 +35x4 is true or false. explain
Marizza181 [45]
False, because it would no longer be 18 alone because of the disturbutive property.
8 0
2 years ago
The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse
diamong [38]

Answer:  The answer is cosine of that acute angle.


Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

Thus, the ratio is cosine of the acute angle.

7 0
2 years ago
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