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jenyasd209 [6]
4 years ago
5

Can some one help me with me math homework ? Thanks I appericiate that.

Mathematics
1 answer:
allochka39001 [22]4 years ago
3 0
I will. But one question is it Grade 8 math

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Using the p-value rule, if a null hypothesis is rejected at a significance level of 0.01, it will ________ be rejected at a sign
igomit [66]

Answer:

<u>always</u>

Step-by-step explanation:

For this hypothesis test:

<u>The Decision rule: </u> To reject the null hypothesis H_o if the p-value is lesser than < the significance level.

At the level of significance 0.01, the null hypothesis is rejected.

So, p-value < 0.01 and this typically shows that p-value is < 0.05.

Therefore, it will <u>always</u> be rejected at ∝ = 0.05

8 0
3 years ago
A chemist is using 336 milliliters of a solution of acid and water. If 16.4% of the solution is acid, how many milliliters of ac
RUDIKE [14]

Answer:

Amount of acid = 55.1 mm (Approx)

Step-by-step explanation:

Given:

Amount of solution = 336 mm

Percentage of acid = 16.4%

Find:

Amount of acid

Computation:

Amount of acid = Amount of solution x Percentage of acid

Amount of acid = 336 x 16.4%

Amount of acid = 55.1 mm (Approx)

7 0
3 years ago
A quadratic function f(x)f(x) is hidden from view. You must find the xx-intercept(s) of f(x)f(x) and write the answer(s) in the
Alika [10]

f(x) should be in canonical form. So it must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient and is the vertex

Step-by-step explanation:

A quadratic function has a unique extreme value in its vertex. That value might be a maximum or a minimum depending on the sign of the main coefficient of the quadratic function. In order to quickly obtain the vertex, the quadratic must be written in canonical form. That means that f(x) must have the form

f(x)=a(x-x_v)^2+y_v

Where a is the main coefficient (which should be negative so that a minimum exists in the first place) and is the vertex. If f(x) is written in that form, then it will be easier to find the minimum of f(x), which is the vertex

Hence for the quadratic function below

\begin{gathered} f(x)=(x-2)^2-9 \\ f(x)=x^2-4x-5 \\ ax^2+bx+c \\ a=1,\text{ b=-4, c=-5} \\ x_v=-\frac{b}{2a} \\ x_v=\frac{-(-4)}{2(1)} \\ x_v=\frac{4}{2} \\ x_v=2 \\ y_v=2^2-4(2)-5 \\ y_v=-9 \\ (x,y)\longrightarrow(2,-9) \end{gathered}

Hence there is only one x- intercept and answer is (2, -9)

7 0
2 years ago
Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
3 years ago
Geometry: Which answer is correct?
IrinaVladis [17]

Answer:

ANSWER D

Step-by-step explanation:

3 0
4 years ago
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