Question

1. Find the surface area of the right triangular prism below.

Answer 1

Answer:

2. D. $\displaystyle 9\:in.$

1. C. $\displaystyle 408\:in.^2$

Step-by-step explanation:

$\displaystyle 2A_B + h[c + b + a] = S.A.$

Area of a Triangle [keep this in mind to find the base area]:

$\displaystyle \frac{1}{2}bh = A, \frac{1}{2}hb = A, or\:\frac{hb}{2} = A$

Pythagorean Theorem [You will need this theorem to find the lengths of both hypotenuses on both triangular bases]:

$\displaystyle a^2 + b^2 = c^2$

2. $\displaystyle 2A_B + p[c + 3 + 4] = 120 → 2[6] + p[5 + 3 + 4] = 120 \\ \\ 12 + 12p = 120 → 108 = 12p; 9 = p$

1. $\displaystyle 2A_B + 15[c + 6 + 8] = S.A. → 2[24] + 15[10 + 6 + 8] = S.A. \\ \\ 48 + 15[24] = S.A. → 48 + 360 = S.A.; 408 = S.A.$

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