Can someone help with this?

Mathematics

2 answers:

alekssr [168]3 years ago

8 0

Hey

8x^2-4x

4x is the greatest common factor.

B answer

TEA [102]3 years ago

5 0

The answer is
Answer:4x(2x−1)

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19. In the triangle ABC, the side lengths are BC = 14 and AC = 7. What's the angle measurement of B?

mr Goodwill [35]

Answer:

Is not possible to compute the angle under those conditions.

Step-by-step explanation:

You need more information, I will be more specific, there is a book called "Geometry" by Moise Downs where the following theorem is stated on the chapter 7.

Let ΔABC and ΔDEF be two triangles where AB = DE and AC = DF if

∠A > ∠D then BC > EF, which in simple terms means that, if two sides are equal, the angle between them can vary as much as you want and that will directly imply the size of the third size of your triangle.

Therefore, there is information missing in order to solve the question

8 0

3 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.