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vaieri [72.5K]
3 years ago
14

Elena is painting a fence she has already determined that she needs 1 gallon of paint total for each 10 feet of fencing to finis

h the entire job the fencing will enclose a rectangular yard that is 3 yards long and 2 yards wide how much paint does Elena need?
Mathematics
2 answers:
sp2606 [1]3 years ago
6 0

1 yard is 3 feet

3 yards times 3 = 9 feet

2 yards times 3= 6 feet

9+6= 15ft

elena will need 2 gallons of paint

Gwar [14]3 years ago
3 0

Answer:

The answer is 3 gallons of paint.

Step-by-step explanation:

Elena is painting a fence she has already determined that she needs 1 gallon of paint total for each 10 feet of fencing.

The dimensions of yard are = 3 yards by 2 yards.

We will convert the yards in feet.

1 yard = 3 feet

So, the dimensions are = 9 feet by 6 feet

Perimeter will be = (2\times9)+(2\times6)

= 18+12=30 feet

Now its given that, 1 gallon paints 10 feet of fencing.

So, to paint 30 feet of fence, the paint required will be = 30/10=3 gallons.

Therefore, the answer is 3 gallons of paint.

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If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
Natalka [10]

Answer:

<h2>(h - g)( - 2) = 18</h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3>(h - g)(x) =  {2x}^{2}  - 5x + 2 - ( {x}^{2}  - 2x - 6)  \\  =  {2x}^{2}  - 5x + 2 -  {x}^{2}  + 2x + 6 \\  =  {2x}^{2}  -  {x}^{2}  - 5x + 2x + 2 + 6</h3><h3>(h - g)(x) =  {x}^{2}  - 3x + 8</h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3>(h - g)( - 2) =  ({ - 2})^{2}  - 3( - 2) + 8 \\  = 4 + 6 + 8 \\  = 10 + 8</h3>

We have the final answer as

<h3>(h - g)( - 2) = 18</h3>

Hope this helps you

7 0
3 years ago
Write an equation in standard form for:
Tasya [4]
Hello!
When finding the perimeter of a rectangle, you have to consider the properties of a rectangle. A rectangle has two pairs of equal sides where one is the width, while the other one is the length. 
Now looking back at your question, it says "... a rectangle that is x units wide" ⇒ you let the width = x ; this is the same with "y units long" ⇒ length = y. Perimeter can just be : P = 24.  
Therefore,
The equation would be:
x + x + y + y = P. 
2x + 2y = P.
(Sub in P = 24)
∴ 2x + 2y = 24. (This should be your answer.)
:) Good luck (Message me if you have any problem)








5 0
3 years ago
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mr_godi [17]
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3 years ago
he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s
sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

P(X

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

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b) between 8 and 9 minutes:

P(8< X' <9) =[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

NORMSDIST(6.366)-NORMSDIST(-1.47)

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0
3 years ago
Find value of x and y
tatyana61 [14]

Step-by-step explanation:

x = 144 ( corresponding angle)

y = 180- 144 ( linear pair)

y= 36°

6 0
3 years ago
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