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3 years ago

Determine if you are finding the part ,percent,or whole.12 is 50%of what number

Mathematics

1 answer:

Zina [86]3 years ago

6 0

Answer:

wdwwwdd

Step-by-step explanation:

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In a mathematics class, the following test scores were recorded for a student. Find the mode 90, 99, 95, 78, 81, 89

tatyana61 [14]

Answer:

78,81,89,90,95,99

Step-by-step explanation:

there is no mode because none of the numbers repeat themselves

8 0

2 years ago

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How much do you need to subtract from 87/10 to make 8

strojnjashka [21]

Answer:

i feel like you need 76 from the 87

Step-by-step explanation:

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2 years ago

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Find the range of ƒ(x) = –x + 4 for the domain {–3, –2, –1, 1}.

qaws [65]

Answer:

range {3, 5, 6, 7 }

Step-by-step explanation:

to find the range substitute each value of x from the domain into f(x)

f(- 3) = -(- 3) + 4 = 3 + 4 = 7

f(- 2) = - (- 2 + 4 = 2 + 4 = 6

f(- 1) = - (- 1) + 4 = 1 + 4 = 5

f(1) = - 1 + 4 = 3

range y ∈ { 3, 5, 6, 7 }

7 0

3 years ago

Please help ASAP, thank you and have a good night/day❤️

wolverine [178]

Answer:

1. 6 (3)^2 = 54 ft ^2

2. 6 (2)^2 = 24 ft ^2

3. 54+ 24 = 78 ft^2

5 0

2 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago