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madreJ [45]
3 years ago
15

Can someone help me with this please ?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

If the triangle is a right triangle, then

       (3x)² + x² = (10)² .

         9x² + x² = 100

             10x²  = 100

                 x²  =  10

                 x  =  √10  =  approx. 3.1622...

If ' x ' is <em>anything less than √10</em> , then the short sides are too short
to make a right angle at the top, and the angle where they meet
is obtuse.

' x ' has to be greater than  2.5 ... otherwise the two short sides
can't stretch far enough to reach both ends of the long side (10) .

So, if    2.5  <  x  <  √10 , then there is a triangle, and it's obtuse.


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Answer:

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Step-by-step explanation:

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6 0
3 years ago
The length of ZX is 2 units. What is the perimeter of triangle XYZ?
dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>

To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>

The formula to calculate the <u>distance</u> between to <u>points</u> is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


Step 1

Find the <u>distance</u> ZY

Z(1,0)\\Y(3,1)  

substitute the values


d=\sqrt{(1-0)^{2}+(3-1)^{2}}


dZY=\sqrt{5}\ units


Step 2

Find the <u>distance</u> XY

X(-1,4)\\Y(3,1)  

substitute the values


d=\sqrt{(1-4)^{2}+(3+1)^{2}}


dXY=\sqrt{25}=5\ units  

Step 3

Find the <u>perimeter</u> of the <u>triangle</u>

P=ZX+ZY+XY

we have

dZX=2\sqrt{5}\ units


dZY=\sqrt{5}\ units


dXY=5\ units  

Substitute

P=(2\sqrt{5}+\sqrt{5}+5)\ units

therefore

the answer is

P=(3\sqrt{5}+5)\ units

4 0
3 years ago
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