1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
4 years ago
9

There are 252 pieces of candy in a 14-ounce jar. How many pieces of candy are there per ounce in the jar ?

Mathematics
2 answers:
BigorU [14]4 years ago
7 0
The question gives us the amount of candy (252 pieces) and the number of ounces that the jar holds (14 ounces).

We can then find the pieces of candy per ounce by dividing the number of pieces by the amount of ounces that the jar holds:

\frac{252 pieces}{14 ounces}
\frac{18pieces}{1ounce}

Now we know that there are 18 pieces of candy per one ounce that the jar can hold.
scZoUnD [109]4 years ago
7 0
For this problem I would take 252 (the number of pieces of candy) and divide it by 14 ( the number of ounces).

252 ÷ 14

Which equals 18 pieces of candy per ounce
You might be interested in
If you remove the last digit (one’s place) from a 4-digit whole number, the resulting number is a factor of the 4-digit number.
shutvik [7]

Answer:

  900

Step-by-step explanation:

We assume that your 4-digit number must be in the range 1000 to 9999. Clearly, any number ending in zero will meet your requirement:

  1000/100 = 10

  3890/389 = 10

However, the requirement cannot be met when the 1s digit is other than zero.

__

For some 3-digit number N and some 1s digit x, the 4-digit number will be

  4-digit number: 10N+x

Dividing this by N will give ...

  (10N+x)/N = 10 remainder x

N will only be a factor of 10N+x when x=0.

So, there are 900 4-digit numbers that meet your requirement. They range from 1000 to 9990.

6 0
3 years ago
2x + 3/ x - 4 - 2x - 8/ 2× + 1 = 1
Debora [2.8K]
\dfrac{2x+3}{x-4}-\dfrac{2x-8}{2x+1}=1\ \ \ |the\ domain\ D:x\neq4\ and\ x\neq-\dfrac{1}{2}\\\\\dfrac{(2x+3)(2x+1)}{(x-4)(2x+1)}-\dfrac{(2x-8)(x-4)}{(2x+1)(x-4)}-1=0\\\\\dfrac{4x^2+2x+6x+3}{2x^2+x-8x-4}-\dfrac{2x^2-8x-8x+32}{2x^2+x-8x-4}-\dfrac{2x^2+x-8x-4}{2x^2+x-8x-4}=0\\\\\dfrac{4x^2+8x+3}{2x^2-7x-4}-\dfrac{2x^2-16x+32}{2x^2-7x-4}-\dfrac{2x^2-7x-4}{2x^2-7x-4}=0\\\\\dfrac{4x^2+8x+3-2x^2+16x-32-2x^2+7x+4}{2x^2-7x-4}=0\\\\\dfrac{31x-25}{2x^2-7x-4}=0\iff31x-25=0\\\\31x=25\\\\\boxed{x=\frac{25}{31}}
6 0
3 years ago
jonathan ran 5 days this week. the most he ran in one day was 3.5 miles. write an inequality that shows the distance jonathan co
poizon [28]
Let m represent the number of miles this guy runs in a day.
He runs every day, so the minimum number of miles has to be greater than 0.
According to the problem statement, the max number of miles is 3.5 miles or less.

Translate this into a (symbolic) inequality.
4 0
3 years ago
Combine like terms to simplify.<br><br> 2. 3v + w +8 - 2n
AURORKA [14]
3v + w +8 - 2n 
<span>
Simplifying 3v + w + 8 + -2n

Reorder the terms: 8 + -2n + 3v + w
 
Hopes it helped!
</span>
4 0
3 years ago
Factor 8q^2 + 3m + 4qm + 6q=
SIZIF [17.4K]
8q² + 4qm + 6q + 3m
4q(2q) + 4q(m) + 3(2q) + 3(m)
4q(2q + m) + 3(2q + m)
(4q + 3)(2q + m)
8 0
4 years ago
Other questions:
  • A stack of 8 different cards are shuffled and spread out face down. if 5 cards are turned face up, how many different 5-card com
    6·1 answer
  • Why does <br> (x=m)2 + (y-d)2=s2 <br> make a circle
    10·2 answers
  • 2x-5y=10 in slope intercept form​
    15·1 answer
  • Convert 77 millimeters to inches.
    11·1 answer
  • you have 1 blue block you also have 3 yellow blocks you want to chose a green block and make the probability equal to 50% how ma
    6·1 answer
  • Four times the difference of 15 and 6
    13·1 answer
  • Solve for y<br> y/6-4=2<br> y= what
    12·1 answer
  • Is 5/6 greater or is 9/10 greater
    9·2 answers
  • What is the difference to the nearest hundredth of a unit between the two zeros
    10·1 answer
  • 756 x 300??????? ?????????
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!