Answer:
BL = 2
Step-by-step explanation:
Given:
AL = 3
AC = 10
BC = 9
AL = AM = 3 (tangents drawn form am external point)
CM = AC - AM
CM = 10 - 3
CM = 7
CM = CN = 7 (tangents drawn form am external point)
BN = BC - CN
BN = 9 - 7
BN = 2
BN = BL = 2 (tangents drawn form am external point).
BL = 2
Answer:
19/8
Step-by-step explanation:
To find the mixed number
Take the denominator times the whole number
8*2 = 16
Add the numerator
16+3 = 19
Put this over the denominator
19/8
Hello!
The answer is:
Luke did a work of 308N.m or 308 Joules.
<h2>
Why?</h2>
When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.
We can calculate the work done by using the following equation:

Where,
Work is the transferred energy.
Force, is the force applied to the object.
Distance, is the distance covered due to the applied force.
α, is the angle at the work is done.
We are given the following information to calculate the work done:

So, substituting the given information into the equation to calculate work, we have:

Hence, we have that Luke did a work of 308N.m or 308 Jouls.
Have a nice day!
Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
since the graph has direct variation as data in x axis increases y also increases.
so we need to find how many miles travelled per galloon .
we distance travelled per gallon =total distance travelled/galoons of fuel used.

for part b) slope=rise/run



slope of the graph is 2