M
=
0
O
r
m
=
23
15
Explanation:
1
3
m
+
6
m
−
9
3
m
=
3
m
−
3
4
m
⇒
1
+
6
m
−
9
3
m
=
3
m
−
3
4
m
⇒
−
8
+
6
m
3
m
=
3
m
−
3
4
m
⇒
(
−
8
+
6
m
)
×
4
m
=
(
3
m
−
3
)
×
3
m
⇒
−
32
m
+
24
m
2
=
9
m
2
−
9
m
⇒
−
32
m
+
24
m
2
−
9
m
2
+
9
m
=
0
⇒
15
m
2
−
23
m
=
0
⇒
m
(
15
m
−
23
)
=
0
m
=
0
Or
15
m
−
23
=
0
⇒
15
m
=
23
⇒
m
=
23
15
Answer:
Volume injected = 1.65 ml
Step-by-step explanation:
mass of Demerol =45 mg.
density of pre-filled in syringe = 50 mg/ml
Volume = 45/50 = 0.9 ml
For atropine mass = 0.3 mg
density= 400 mcg/ml [ Note : 1 mcg = 0.001 mg]
volume filled = 0.3/400(0.001) = 0.75 ml
So, the total volume filled = 0.75+0.9 = 1.65 ml
Answer:
FIVE
Step-by-step explanation:
Part A: f(t) = t² + 6t - 20
u = t² + 6t - 20
+ 20 + 20
u + 20 = t² + 6t
u + 20 + 9 = t² + 6t + 9
u + 29 = t² + 3t + 3t + 9
u + 29 = t(t) + t(3) + 3(t) + 3(3)
u + 29 = t(t + 3) + 3(t + 3)
u + 29 = (t + 3)(t + 3)
u + 29 = (t + 3)²
- 29 - 29
u = (t + 3)² - 29
Part B: The vertex is (-3, -29). The graph shows that it is a minimum because it shows that there is a positive sign before the x²-term, making the parabola open up and has a minimum vertex of (-3, -29).
------------------------------------------------------------------------------------------------------------------
Part A: g(t) = 48.8t + 28 h(t) = -16t² + 90t + 50
| t | g(t) | | t | h(t) |
|-4|-167.2| | -4 | -566 |
|-3|-118.4| | -3 | -364 |
|-2| -69.6 | | -2 | -194 |
|-1| -20.8 | | -1 | -56 |
|0 | -28 | | 0 | 50 |
|1 | 76.8 | | 1 | 124 |
|2 | 125.6| | 2 | 166 |
|3 | 174.4| | 3 | 176 |
|4 | 223.2| | 4 | 154 |
The two seconds that the solution of g(t) and h(t) is located is between -1 and 4 seconds because it shows that they have two solutions, making it between -1 and 4 seconds.
Part B: The solution from Part A means that you have to find two solutions in order to know where the solutions of the two functions are located at.
