A 8 as the 2 labelled lengths will be the same; 2 x 8 = 16
Correct Question:
Which term could be put in the blank to create a fully simplified polynomial written in standard form?
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y3)
Options

Answer:

Step-by-step explanation:
Given
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
Required
Fill in the missing gap
We have that:
![8x^3y^2 -\ [\ \ ] + 3xy^2 - 4y^3](https://tex.z-dn.net/?f=8x%5E3y%5E2%20-%5C%20%5B%5C%20%5C%20%5D%20%2B%203xy%5E2%20-%204y%5E3)
From the polynomial, we can see that the power of x starts from 3 and stops at 0 while the power of y is constant.
Hence, the variable of the polynomial is x
This implies that the power of x decreases by 1 in each term.
The missing gap has to its left, a term with x to the power of 3 and to its right, a term with x to the power of 1.
This implies that the blank will be filled with a term that has its power of x to be 2
From the list of given options, only
can be used to complete the polynomial.
Hence, the complete polynomial is:

Answer:
2/15
Step-by-step explanation:
4/5-2/3
12/15-10/15
2/15
Answer:

Step-by-step explanation:
Given



<em>See attachment</em>
Required
Which sine of angle is equivalent to 
Considering 
We have:
--- i.e. opposite/hypotenuse
So, we have:

Divide by 4

Hence:
is correct