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Sati [7]
3 years ago
9

Please help me with this one

Mathematics
1 answer:
jonny [76]3 years ago
3 0

Answer: 1,885.10

Step-by-step explanation:

I think you just add them all and then round right

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Which statement is correct? StartFraction 1 inch Over 2.54 centimeters EndFraction = StartFraction 7 inches Over 17.68 centimete
Bond [772]

Answer:

1 yard / 36 inches = 7 yards / 252 inches

Step-by-step explanation:

1 inch / 2.54cm = 7 inch/ 17.68 cm

1 foot / 12 inches = 7 feet / 74 inches

1 yard / 36 inches = 7 yards / 252 inches

1 meter / 3.28 feets = 7 meters / 22.86 feets

To establish the correctness of the statements above , we express the fractions in decimals and see if the right hand side = left hand side

1 inch / 2.54cm = 7 inch/ 17.68 cm

0.3937007 = 0.3959276 (incorrect)

1 foot / 12 inches = 7 feet / 74 inches

0.0833333 = 0.0945945 (incorrect)

1 yard / 36 inches = 7 yards / 252 inches

0.0277777 = 0.0277777 (correct)

1 meter / 3.28 feets = 7 meters / 22.86 feets

0.3048780 = 0.3062117 (incorrect)

3 0
3 years ago
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2 What is the height of the parallelogram in the example?<br> How did you find the height?
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Answer:

the answer is 50

Step-by-step explanation:

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3 years ago
A new member of your team is visually impaired. He's having a hard time reading his computer screen. How can you show that you v
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job" (and any subsequent words) was ignored because we limit queries to 32 words.

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Step-by-step explanation:

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3 years ago
An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the
DedPeter [7]

<em><u>The inequality can be used to find the interval of time taken by the object to reach the height  greater than 300 feet above the ground is:</u></em>

d = -16t^2 + 1000

<em><u>Solution:</u></em>

<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the  formula:</u></em>

d = -16t^2 + 1000

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

-16t^2 + 1000 > 300

Solve the inequality

Subtract 1000 from both sides

-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700

16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61

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Therefore,

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