Answer:
1900
Step-by-step explanation:
1 kg = 1000g
1.2kg = x
<u>1</u><u> </u><u>kgx</u> = <u>1</u><u>2</u><u>0</u><u>0</u><u> </u><u>kg.g</u>
1kg. 1kg
x = 1200 g
1 decagram = 10g
40 decagram = x
<u>1</u><u> </u><u>dg.x</u> = <u>4</u><u>0</u><u>0</u><u> </u><u>dg.g</u>
1 dg. 1 dg
x = 400g
so the total= 1200g +300 + 400g=1900g
without the unit = 1900
Answer:
no clue
Step-by-step explanation:
figure it out by yourself
Answer:
i think its 10 if not then 387
Step-by-step explanation:
Answer:
Both 
and 
are solutions to the system.
Step-by-step explanation:
In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.
Step 1: Plug into 
The solution verifies the equation.
Step 2: Plug into 
The solution verifies both equations. Therefore, is a solution to this system.
Now we must check if the second point is also valid.
Step 3: Plug into
Step 4: Plug into
The solution verifies both equations. Therefore, is another solution to this system.
An equilateral triangle has all side lengths the same, and all angles are 60 degrees. Using this we can split the triangle along its altitude to get two right triangles with a hypotenuse of length 10 and a base of 1/2 of the original length, so 5. Now we can either use the Pythagorean theorem (a^2+b^2=c^2) or the fact that it is a 30 60 90 triangle (angles measure at 30 60 and 90 degrees) Pythagorean theorem is probably easier.
It stated that the squares of the two legs of a right triangle add to the square of the hypotenuse. So a(the altitude)^2+5(the base)^2=10(the hypotenuse)^2
A^2+5^2=10^2
A^2+25=100
A^2=75
A=sqrt(75)
A=5*sqrt(3)
Final answer:
The altitude of an equilateral triangle with side length 10 is 5sqrt(3), or about 8.66
