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3 years ago

Help meeeeeee plz I need helppppppppppplp

Mathematics

1 answer:

MatroZZZ [7]3 years ago

7 0

Jessica runs fastest because her time/second is about 10 seconds while brookes is around 12.

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In the coordinate plane, when you move an ordered pair (x,y) to the right, _______

guapka [62]

A. The x values get larger Bc your moving right on the x-axis

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3 years ago

Classify the triangle by its sides. The lengths of the sides are 6, 8, and 8.

ziro4ka [17]

Answer:

Isosceles

Step-by-step explanation:

An icosceles triangle has two sides with the same length.

6, 6, 8

6, 6, 8

Isosceles

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2 years ago

Read 2 more answers

On average, Stan drinks 34 of a 8 ounce glass of water in 12 of an hour. How much water does he drink in an hour?

baherus [9]

Answer:22.6

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Hope this helps.

3 0

3 years ago

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

Find the exact solutions of the system

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

Find the values of y

First solution

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

Second solution

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

First solution

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

Help lol the question is on the picture please help!

valina [46]

here u go, remember the ratio

7 0

3 years ago

Help meeeeeee plz I need helppppppppppplp​

Help meeeeeee plz I need helppppppppppplp