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mel-nik [20]
4 years ago
8

Write an equation to solve each problem and then solve it. b In a 3-digit number, the hundreds digit is four more than the ones

digit and the tens digit is twice the hundreds digit. If the sum of the digits is 12, find the three digits. Find the number.
Mathematics
1 answer:
Misha Larkins [42]4 years ago
3 0

Answer:

digits are: 0, 4, 8. The required number is: 480.

Step-by-step explanation:

→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.

→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.

→ After evaluation this equation, x=0 - this is ones digit;

→ x+4=0+4=4 - this is hundreds digit;

→ 2(x+4)=2(0+4)=8 - this is ten digit.

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Hope this helps you...

6 0
3 years ago
Please help
Eva8 [605]

146.65 becuase 12.3 plus 25.75 plus 108.6 equals 146.65

8 0
3 years ago
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How do you find 3w-6w+3w×7×7×6×5÷9+2
Viktor [21]
Let's remember orders of operations as we go through the craze of this problem.
We need to multiply or divide from left to right.
3w-6w+3w×7×7×6×5÷9+2
3w-6w+21w×7×6×5÷9+2
3w-6w+147w×6×5÷9+2
3w-6w+882w×5÷9+2
3w-6w+4,410w÷9+2
3w-6w+490w+2
-3w+490w+2
487w+2
To check that we simplified the expression right, I like to put in 1 for w and test it in the original expression and then the simplified expression (not needed).
487+2=489
3-6+3×7×7×6×5÷9+2=489
So that expression equals 487w+2.
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4 years ago
The graph below shows a system of equations: The x coordinate of the solution to the equation is _______. (5 points)
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