Step-by-step explanation:
1. solution,
length of rectangle A(l)=3.1units
breadth of rectangle A(b)=1units
now,
area of rectangle A=l×b
=3.1units×1units
=3.1 sq units
2.solution,
length of rectangle B(l)=3.1units
breadth of rectangle B (b)=0.4units
now,
area of rectangleB=l×b
=3.1units×0.4units
=1.24 sq units
3.solution,
length=3.1units
breadth=1.4units
area =lxb
=3.1units x 1.4units
=4.34units
Answer:
57
Step-by-step explanation:
How I did this was 513 divided by 9 so the equation that I did was 513/9.
Answer:
decreasing
Step-by-step explanation:
"Increasing" means the graph is going up from left to right.
"Decreasing" means the graph is going down from left to right.
"Constant" means the graph is "flat" (this is not a technical term) it is keeping the same y value, neither going up nor going down.
What can be super confusing is the
(2.2, 5) mentioned in the question. THIS IS NOT A POINT. It is an interval and points and intervals unfortunately have the same notation sometimes.
An "interval" is a section of the graph, here: FROM 2.2 not including 2.2, TO 5 not including 5. These are like the address on the x-axis. If you look at your graph at 2.2 on the x-axis, it is a peak(relative maximum) and it goes down to the right to where x is 5 where it bottoms out (relative minimum) So on that interval, from 2.2 to 5, the graph is DECREASING.
Ln(xy) - 2x =0
slope of the tangent line = derivative of the function
[ln(xy)]' = [2x]'
[1/(xy)] [y + xy'] = 2
y + xy' = 2(xy)
xy' = 2xy - y =y(2x-1)
y' = y(2x-1)/x
Now use x = -1 to find y and after to find y'
ln(xy) = 2x
x=-1
ln(-y) =-2
-y = e^-2
y = - e^-2
y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2
Answer: option 6. from the list
