Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Answer:
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Step-by-step explanation:
Answer:
about 11.5 cm.
Step-by-step explanation:
I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.
a^2+b^2=c^2.
"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.
8^2+b^2=14^2 simplified: 64+b^2=196
Then, I subtracted 64 on both sides, so I would have "b" by itself.
b^2=132
Next, I found the square root of both b^2 and 132, so I would find the true value of "b."
b=11.4891252931
So, the measure of the other leg rounded to the nearest tenth is about 11.5.
