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sergey [27]
3 years ago
7

Figure A is a scale image of Figure B. What is the value of x?

Mathematics
1 answer:
kari74 [83]3 years ago
4 0

Hey there! :)

Answer:

x = 21 units.

Step-by-step explanation:

Since we know Figure A is just Figure B scaled, we can set up a proportion:

\frac{45}{35}= \frac{27}{x}

Cross multiply to solve for x:

45 · x = 35 · 27

45x = 945

Divide both sides by 45:

x = 21 units.

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Given a vector with the initial point, (4,2) and the terminal point, (-3,1), find the vector in unit vector form.
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3 years ago
Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde
zmey [24]

Answer:

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

p_v =P(t_{(19)}>1.638)=0.0589    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

Step-by-step explanation:

Data given and notation    

\bar X=7.03 represent the sample mean

s=9.42 represent the sample standard deviation    

n=20 sample size    

\mu_o =3.58 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :    

Null hypothesis:\mu \leq 3.58    

Alternative hypothesis:\mu > 3.58    

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638    

P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since is a right tailed test the p value would be:    

p_v =P(t_{(19)}>1.638)=0.0589    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.    

7 0
3 years ago
john bought a used truck for 4,500. he made an agreement with the dealer to put 1,500 down and make payments of 350 for the next
pantera1 [17]
So $350 X 10 =$3500

Then, you add the initial $1500,

which means he now has $5000

The difference between $5000 and $4500 is $500,

<span>And $500 is 9% of $4500, </span>

So the deal is equivalent to a yearly interest of 9%

<span>Hope this helps ! :)</span>
8 0
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