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hjlf
3 years ago
10

X/5 = -3 x=____ help

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
X=-15 , when u divide it , you’ll get -3
scZoUnD [109]3 years ago
7 0
I feel like a creep because I’m replying to most of your answers lol. But the answer is x = -15
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Which of the segments below is a secant?<br><br> A. XB<br> B. OB<br> C. XV<br> D. XY
s2008m [1.1K]
A secant of a curve is a line that intersects the curve at a minimum of two distinct points.

So the answer is D. XY
5 0
3 years ago
For f(x) = 3x^2 – X+5, 2f (-3) - f(4)=
Alenkinab [10]

Answer:

3x^2-x+5.2f\left(-3\right)-f\left(4\right) =

3x^2-x-19.6f

Step-by-step explanation:

3x^2-x+5.2f\left(-3\right)-f\left(4\right)

=3x^2-x-5.2f\cdot \:3-f\cdot \:4

=3x^2-x-15.6f-4f

=3x^2-x-19.6f

8 0
3 years ago
Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
Help me pls pls pls pls
Alex Ar [27]

5 2/4 because 3 and 2 are 5 and 1/4 plus 1/2 make up 2/4 meaning its either 5 2/4 or 5 1/2

now i get brainly <3

6 0
3 years ago
Which unit rate is the lowest price per ounce?
Marizza181 [45]
The lowest price per oz is choice A :)
5 0
3 years ago
Read 2 more answers
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