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UkoKoshka [18]
3 years ago
9

What is the answer to the answer to the problem 1 plus 1 need help thank you in advance.

Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

1+1=2

I don't know why you would ask that lol


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B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}

Then by the chain rule,

\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}

So we have

g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}

and we can simplify this by factoring out 18(36-x^2)^{-3/2} to end up with

g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}

5 0
2 years ago
Which equation shows direct variation? A. y-x=1. B. y/x=10. C. y=4/x. D. xy=5
sesenic [268]
C. y=4/x i think.......
7 0
3 years ago
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2.0 x 10³ =<br> Write this number in standard notation
shusha [124]

Answer:

2(10x10x10)

Step-by-step explanation:

3 0
2 years ago
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X(x+1)-1=4<br> ---<br> please help stuck on this question
Sloan [31]

Answer:

x=2

Step-by-step explanation:

use distributive property: x^2+2x-1=4

remove the -1 by adding 1 on both sides: x^2+2x=5

use the guadratic fromula:  ax²+bx+c=0

plug in the equation x^2+2x-5=0

a,b and c are the coefficients to plug into the formula

a=1, b=2, c=-1

Finally, you will find that x=2

8 0
2 years ago
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HELPPPPP!!! PLEASEEEEEEE
8090 [49]

Answer:  $1.5

Step-by-step explanation:

$3.00 divided by 2 pounds is $1.5

$4.50 divided by 3 pounds is $1.5

and $6.00 divided by 4 pounds $1.5

8 0
2 years ago
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