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3 years ago

14400:(270-х)+520=680

Mathematics

1 answer:

Nataly_w [17]3 years ago

7 0

X=110 because 270-110=160 and 160+520=680.

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When the function f(x) = 6(9)x is changed to f(x) = 6(9)x + 1, what is the effect? (5 points) There is no change to the graph be

amm1812

Answer:

The y-intercept is 1 space higher.

Step-by-step explanation:

y goes up by 1.

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2 years ago

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The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?

solmaris [256]

Answer:

Dividend

$=x^4 + 5 x^3 - 3 x - 15$

Divisor

$=x^3-3$

The rule of division of polynomial which is same as division of real numbers states that

Dividend = Divisor × Quotient + Remainder

The division process is shown below.

Quotient = x+5

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3 years ago

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(3 x 105 ) x (2 x 103 )

anzhelika [568]

Answer:

64,890

Step-by-step explanation:

105×3 =315

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3 years ago

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Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago

Es posible dibujar 9 segmentos de línea de manera que cada segmento interseque exactamente 1 de los otros segmentos?

uysha [10]

Answer: No es posible (It is not possible)

Step-by-step explanation:

The question in english is as follows:

Is it possible to draw 9 line segments so that each segment crosses exactly 1 of the other segments?

A necessary condition for two lines to intersect is that they must be in the same plane (they must be coplanar), being their intersection a single point.

Now, if we want several lines to intersect only once, we need to have an <u>even number</u> of line segments. However, this is not the case because <u>9 is odd. </u>

Therefore, it is not possible.

8 0

2 years ago