Answer:
<em>97.5 sq. ft.</em>
Step-by-step explanation:
Im presuming the question asks to find area of the shaded region.
First of all, the total figure is a rectangle. We can write an expression(in words) for the shaded area.
<em>Shaded Area = Area of Rectangle - Area of Small Triangle(White) - Area of Large Triangle(White)</em>
Now, we find respective areas.
Area of rectangle:
length * width = (5+10) * (12) = 15 * 12 = 180
Area of Small Triangle (white):
A = (1/2) * base * height = (1/2) * 5 * (12-3) = (1/2) * 5 * 9 = 22.5
Area of Large Triangle (white):
A = (1/2) * base * height = (1/2) * 10 * (12) = 60
Now, we find area of shaded region:
<em>Shaded Area = Area of Rectangle - Area of Small Triangle(White) - Area of Large Triangle(White)</em>
<em>Shaded Area = 180 - 22.5 - 60 = 97.5 sq. ft.</em>
Answer:
1. y ax
|
A-------------------------------B
|
------------C---------------------
|
|__________________x ax
for this, your A might be (0,5), B (5,5), C (2,2).
parallel means railroad tracks: same slope, different intercepts.
line AB in this case has a slope of 0, intercept (0,5), so y₁=0x+5 or just y₁=5
the line passing through C also has slope 0, but intercept (0,2), so y₂=0x+2 or just y₂=2
2. perpendicular means that the slopes of two lines multiply out to -1. If line AB has, for example, a slope of 2/3, then the line passing through C would have slope -3/2 (negative reciprocal). To make things easier have either point A or B be on the x or y axis
khan academy has some helpful videos :)
https://www.khanacademy.org/math/geometry/hs-geo-analytic-geometry/hs-geo-parallel-perpendicular-eq/v/perpendicular-lines
Answer:
y = 4
Step-by-step explanation:
Since this is an equilateral triangle, all the sides are equal.
7y + 5 = 9y - 3
5 + 3 = 9y - 7y
2y = 8
y = 8 ÷ 2
y = 4
Answer:
Step-by-step explanation:
Just Quick REVIEW On Formula:
- Curved Surface Area (CSA)=2πrh
- Total Surface Area (TSA)=2πr(r+h)
- Volume (V)=πr2h
- Here, we have Radius(r)=3and Height(h)=10(Given)
- Volume=πr2h
- =π⋅32⋅10
- =282.7433
Solving for both velocities:
16 km / 2 hours = 8 km per hour downstream
16 km / 4 hours = 4 km per hour upsteram
bsw means boat speed in still water cs means current speed
bsw - cs = 4 km per hour
bsw + cs = 8 km per hour
Adding both equaions:
2 bsw = 12 km per hour
boat speed = 6 km per hour
bsw + cs = 8 then
current speed = 2 km per hour
Source: 1728.com/veloccal.htm
