the volume of a pymaird is Volume of a Pyramid<span>A pyramid has a base and triangular sides which rise to meet at the same point. The base may be any polygon such as a square, rectangle, triangle, etc. The general formula for the volume of a pyramid is:Area of the base * Height * 1/3<span>The volume of a pyramid with a rectangular base is equal to:
</span><span>Length_of_base * Width_of_base * Height * 1/3 </span></span>
<span><span>d</span></span>
Answer:
the answer is 32
Step-by-step explanation:
8 plus 8 is 16 times 2 is 32
Answer:
A. Between 3.0 and 3.5 and between 4.0 and 4.5
Step-by-step explanation:
The zeroes of a function occur whenever a value of x returns zero. To predict where the zeroes lie, determine the interval(s) where the function crosses the x-axis. This occurs when either
goes from a negative value to a positive value or vice versa.
From
and
, the y-values go from 4.0 (positive) to -0.2 (negative), respectively. Therefore, there must be a zero in this interval.
From
and
, the y-values go from -0.8 (negative) to 0.1 (positive), respectively. Therefore, there must also be a zero in this interval.
Thus, the zeros of this function occur between 3.0 and 3.5 and between 4.0 and 4.5, leading to answer choice A.
You add all the numbers then divide by how many numbers you have.
(12+15+6)/3 = 11
![2\frac{3}{8}](https://tex.z-dn.net/?f=%202%5Cfrac%7B3%7D%7B8%7D%20)
÷
![1\frac{1}{4}](https://tex.z-dn.net/?f=%201%5Cfrac%7B1%7D%7B4%7D%20)
equals
![1\frac{9}{10}](https://tex.z-dn.net/?f=%201%5Cfrac%7B9%7D%7B10%7D%20)
.
First, convert
![2 \frac{3}{8}](https://tex.z-dn.net/?f=2%20%5Cfrac%7B3%7D%7B8%7D%20)
to improper fraction. Use this rule:
![a \frac{b}{c}](https://tex.z-dn.net/?f=a%20%5Cfrac%7Bb%7D%7Bc%7D%20)
=
![\frac{ac+b}{c}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bac%2Bb%7D%7Bc%7D%20)
. Your problem should look like:
![\frac{2x8+3}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x8%2B3%7D%7B8%7D%20)
÷
![1\frac{1}{4}](https://tex.z-dn.net/?f=%201%5Cfrac%7B1%7D%7B4%7D%20)
.
Second, simplify 2 x 8 to get 16. Your problem should look like:
![\frac{16+3}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%2B3%7D%7B8%7D%20)
÷
![1 \frac{1}{4}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%7D%7B4%7D%20)
.
Third, simplify 16 + 3 to get 19. Your problem should look like:
![\frac{19}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B8%7D%20)
÷
![1 \frac{1}{4}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%7D%7B4%7D%20)
.
Fourth, convert
![1\frac{1}{4}](https://tex.z-dn.net/?f=%201%5Cfrac%7B1%7D%7B4%7D%20)
to improper fraction. Use the same rule as earlier. Your problem should look like:
![\frac{19}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B8%7D%20)
÷
![\frac{4+1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%2B1%7D%7B4%7D%20)
.
Fifth, simplify 4 + 1 to get 5. Your problem should look like:
![\frac{19}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B8%7D%20)
÷
![\frac{5}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B4%7D%20)
.
Sixth, apply this rule: a ÷
![\frac{b}{c}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bb%7D%7Bc%7D%20)
= a ×
![\frac{c}{b}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bc%7D%7Bb%7D%20)
. Your problem should look like:
![\frac{19}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B8%7D%20)
×
![\frac{4}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%7D%20)
.
Seventh, apply this rule:
![\frac{a}{b}](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%7D%7Bb%7D%20)
×
![\frac{c}{d}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bc%7D%7Bd%7D%20)
=
![\frac{ac}{bd}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bac%7D%7Bbd%7D%20)
. Your problem should look like:
![\frac{19x4}{8x5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19x4%7D%7B8x5%7D%20)
.
Eighth, simplify 19 × 4 to get 76. Your problem should look like:
![\frac{76}{8x5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B76%7D%7B8x5%7D%20)
.
Ninth, simplify 8 × 5 to get 40. Your problem should look like:
![\frac{76}{40}](https://tex.z-dn.net/?f=%20%5Cfrac%7B76%7D%7B40%7D%20)
.
Tenth, simplify. Your problem should look like:
![\frac{19}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B10%7D%20)
.
Eleventh, convert to mixed fraction. Your problem should look like:
![1 \frac{9}{10}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B9%7D%7B10%7D%20)
which is the answer.
Answer as mixed number form:
![1\frac{9}{10}](https://tex.z-dn.net/?f=%201%5Cfrac%7B9%7D%7B10%7D%20)
.
Answer as exact form:
![\frac{19}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B10%7D%20)
.
Answer as decimal form: 1.9.