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4 years ago

I need help solving this

Mathematics

2 answers:

mylen [45]4 years ago

7 0

Simple...

4.) -8-x=x-4x

So, what you want to do is isolate x.

Which means that you must move x to one side, and any other variables to the other side.

-8-x=x-4x

-8-x=-3x

-8-x=-3x
+x +x

-8=-2x

$\frac{-8}{-2} = \frac{-2x}{2}$

4=x

Thus, your answer.

To check your work...plug in x.

-8-x=x-4x

-8-4=4-4(4)

-12=4-(16)

-12=-12

Thus, you know your answer is correct.

Tcecarenko [31]4 years ago

5 0

To solve equatins, remember to do the same to both sides and get the x by itself

-8-x=x-4x
-8-x=-3x
add x both sides
-8=-2x
divide -2
4=x

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Which 2 values of x are roots of the polynomial below?

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Given:

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To find the roots we have to take $f(x) = 0$

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$3x^{2} -3x+1 = 0$

Formula

By quadratic formula, the root of the equation $ax^{2} +bx+c = 0$ is,

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Now,

Putting, $a=3, b=-3, c=1$ we get,

$x = \frac{3+\sqrt{3^{2}-4(3)(1) } }{(2)(3)}$ and $\frac{3-\sqrt{3^{2}-4(3)(1) } }{(2)(3)}$

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Hence,

The values of the roots of the given polynomial are $x=\frac{3+\sqrt{-3} }{6}$ and $x=\frac{3-\sqrt{-3} }{6}$

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12345 [234]

Answer:

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Step-by-step explanation:

Distance = rate • time.

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