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3 years ago

Find the balance in each account after the given period. $8000 principal earning 5% compounded annually, after 6 yr

2 answers:

4 0

Hi there! The formula for finding compound interest is P(1 + r)^t, with P = principal (initial amount), r = rate (interest rate), and t = time in years. First off, let's add 1 to the percentage rate in decimal form. 5% is 0.05 as a decimal. 1 + 0.05 is 1.05. Now, because we are looking for the amount after 6 years, we will raise that decimal to the 6th power. 1.05^5 is 1.34009564062. This is a long decimal, but do not delete it from your calculator. You must multiply that number by the principal, which is 8,000. When you multiply the numbers together, you get 10,720.765125 or 10,720.77 when rounded to the nearest hundredth. There. The balance of the account after 6 years is $10.720.77.

Darya [45]3 years ago

3 0

Answer:

The balance in the account after the given period is $\$10,720.77$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=6\ years\\ P=\$8,000\\ r=0.05\\n=1$

substitute in the formula above

$A=\$8,000(1+\frac{0.05}{1})^{1*6}=\$10,720.77$

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3 years ago

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Step-by-step explanation:

y-intercept: x=0 ,f(0)=-10

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3 years ago

For the following exercises, find the x- and y-intercepts of the graphs of each function.

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The x- and y-intercepts of the graphs of the function described are; (2,0) and (4,0) respectively.

<h3>What are the x- and y-intercepts of the graph of the function?</h3>

It follows from the task content that the function given is; f(x) = −2| x +1 | + 6.

Since the x- and y-intercepts corresponds to x and y values for which y and x are zero respectively, it follows that;

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0 = -2(x+1) + 6

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Read more on y-intercept;

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2 years ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

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3 years ago

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prohojiy [21]

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3 years ago