whats the question?????????????????????
Answer:
interent just turn on chrome explore fire fox yahhoo
Explanation:
Answer:
Check the explanation
Explanation:
1.
System = 256Byte = 8 bit
Cache = 64B , block size = 16 byte.
A) Direct Mapped Cache:
Block offset = log (Block size) = log 16 = 4bit
Total # of block inside cache = 4.
Therefore index offset = log 4 = 2bit.
Remaining is tag bits.
Therefore tag bits = 8-(4+2) = 8-6 = 2 bits
Tag Index offset Block offset
(2 bits) (2 bits) (4 bits)
Fully associative cache :
In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.
Therefore tag bits = 8-block offset bit= 8-4 =4bits
Tag Block offset
(4 bits) (4 bits)
Lower range tones generally require larger speakers.
It's no secret that lower range tones generally require larger speakers. This is because lower frequencies have longer wavelengths, and thus require more physical space to produce.
While this may seem like a simple concept, there are a few things to keep in mind when it comes to speaker size and low frequency response. First, larger speakers can usually reproduce lower frequencies more efficiently than smaller ones. Second, the size of the speaker's enclosure also plays a role in how well it can reproduce low frequencies.
A larger enclosure will typically have an easier time reproducing low frequencies than a smaller one.
Keep these things in mind when selecting speakers for your system. If you're looking for accurate low frequency reproduction, make sure to choose speakers with larger drivers and enclosures.
Learn more on speakers here:
brainly.com/question/14649463
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Answer:
Presentation Quality
Explanation:
It will be full quality as it is from when your presenting
