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dem82 [27]
4 years ago
5

1-2 sin e cos 20-2 sin 40 = cos (20)

Mathematics
1 answer:
natka813 [3]4 years ago
8 0

Answer:

No this is not the same as cos(2Ф)

Step-by-step explanation:

First I changed the cos^{2}Ф into 1-sin^{2}Ф

I then foiled the (1-2sin^{2}Ф)(1-sin^{2}Ф) and that resulted in 1-sin^{2}Ф-2sin^{2}Ф+2sin^{4}Ф

From there, I then cancelled the two 2sin^{4}Ф and combined like terms and was left with 1-3sin^{2}Ф

Now 1-3sin^{2}Ф ≠ cos(2Ф)

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Step-by-step explanation:

<u>Step 1:  Multiply</u>

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(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

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Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

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