Which of the following statements about perpendicular lines is true?

sergey [27]

19 i think though im pretty sure it is

5 0

3 years ago

Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput

Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so $p = 0.53$

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 0 successes, so x = 0.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{0}.(0.47)^{4}$

$P = 0.0488$

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 4.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{4}.(0.47)^{0}$

$P = 0.0789$

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 2.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,2}.(0.53)^{2}.(0.47)^{2}$

$P = 0.3723$

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0

3 years ago

Write an algebraic equation or expression or the word phrase<br><br> 25y=5

lidiya [134]

25 times a letter Y = a number 5

5 0

3 years ago

Read 2 more answers

Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.

dusya [7]

$\huge\color{black}\underline\mathbb{\:ANSWER}$

$\green{••••••••••••••••••••••••••••••••••••••••••••••••••}$

Find the values of x for which the denominator is equal to zero for y=3x+5/x-6.

x = −5

x = 6

therefore the answer is

$\green{••••••••••••••••••••••••••••••••••••••••••••••••••}$

$\tt\color{black}{12:14AM}$

$\huge \tt{4/2/22}$

(ノ^_^)ノ

4 0

2 years ago

Read 2 more answers

Solve the following inequality. |3n-2|-2<1

disa [49]

Answer: $\frac{-1}{3}$ < n < $\frac{5}{3}$

<u>Step-by-step explanation:</u>

| 3n - 2 | - 2 < 1

| 3n - 2 | < 3

3n - 2 < 3 and 3n - 2 > -3

3n < 5 and 3n > -1

n < $\frac{5}{3}$ and n > $\frac{-1}{3}$

$\frac{-1}{3}$ < n < $\frac{5}{3}$

Interval Notation: $(\frac{-1}{3},$ $\frac{5}{3})$

Graph: $\frac{-1}{3}$ o--------------------o $\frac{5}{3}$

7 0

3 years ago

Read 2 more answers