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Martin charges $15 for every 5 bags of leaves he rakes. Last weekend, he raked 26 bags of leaves. How much money did he earn

son4ous [18]

$78 is what he earned. 15/5=3. 3*26=78

7 0

3 years ago

Read 2 more answers

Show how to solve -5y+8=-3y+10

marta [7]

-5y+8=-3y+10
-5y+3y=10-8
-2y=2
-2y/-2=2/-2
y=-1

I grouped the alike variable to one side, and the number to the other side, added and subtracted it, divided both sides by -2, and got -1

8 0

3 years ago

Read 2 more answers

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t

motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

$99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = 15.5$

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = 0.4957$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where $\bar{x}$ is the sample mean and Margin of error is given by

$$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample size, s is the sample standard deviation and is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

$MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\$

So the required 99% confidence interval is

$\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0

4 years ago

In how many ways can a family of four be seated at a round table if two brothers must sit together?

Masteriza [31]

The 4-member family can be seated in 4! ways.
The two brothers can be seated together in 2! ways.

Therefore, the total number of ways is
$\frac{4!}{2!} = \frac{4.3.2.1}{2.1} =4*3=12$

Diagrammatically, the result is shown in the figure below. The two brothers are family members 3 and 4, shown in shaded color.

Answer: 12 ways.

6 0

3 years ago

Each issue of Soccer World magazine costs $5.99 at the book store. A 6-month subscription costs $24.99. How much can a reader sa

wel

Answer:the reader will save $10.95 by the 6 months subscription

Step-by-step explanation:The cost of one issue is $5.99

For 6 issues will be 6×$5.99 =$35.94

The amount saved will be $35.94- $24.99= $10.95.

3 0

3 years ago