In statistics the mode of a set of values is the value that occurs most often. Write a program that determines how many pieces o
f pie most people eat in a year. Set up an integer array that can hold responses from 30 people. For each person, enter the number of pieces they say they eat in a year. Then write a function that finds the mode of these 30 values. This will be the number of pie slices eaten by the most people. The function that finds and returns the mode should accept two arguments, an array of integers, and a value indicating how many elements are in the array.
1 answer:
Answer:
see below
Explanation:
The program of interest is the function "findMode[x, n]" in the attached. It is written the Wolfram Language of Mathematica.
The basic idea is that the data in the array is sorted. The sorted array is partitioned into sets of identical elements, and the number in each of those sets is counted. The maximum of those counts is the mode. The location of the maximum count corresponds to the location of the set having that count. We use that location information to pull out the mode value(s).
If there is more than one mode, all are reported.
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An example data array is provided, along with the program output.
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Answer:
Here is the JAVA program. I have added a few more abbreviations apart from LOL and IDK.
import java.util.Scanner; // to take input from user
public class MessageAbbreviation {
public static void main(String[] args) { //start of main() function body
Scanner input = new Scanner(System.in); // create object of Scanner
String abbreviation= ""; //stores the text message abbreviation
/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */
String LOL = "laughing out loud";
String IDK = "i don't know";
String BFF = "best friends forever";
String IMHO = "in my humble opinion";
String TMI = "too much information";
String TYT = "take your time";
String IDC = "I don't care";
String FYI = "for your information";
String BTW = "by the way";
String OMG = "oh my God";
//prompts the user to enter an abbreviation for example LOL
System.out.println("Input an abbreviation:" + " ");
if(input.hasNext()) { // reads the abbreviation form the user
abbreviation= input.next(); }
// scans and reads the abbreviation from user in the abbreviation variable
/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */
switch(abbreviation) {
case "LOL" : System.out.println(LOL);
break;
case "IDK" : System.out.println(IDK);
break;
case "BFF" : System.out.println(BFF);
break;
case "IMHO": System.out.println(IMHO);
break;
case "TMI": System.out.println(TMI);
break;
case "TYT": System.out.println(TYT);
break;
case "IDC": System.out.println(IDC);
break;
case "FYI": System.out.println(FYI);
break;
case "BTW": System.out.println(BTW);
break;
case "OMG": System.out.println(OMG);
break;
default : System.out.println("Unknown"); } } }
Explanation:
The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:
case "LOL" : System.out.println(LOL);
This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.
Anything else entered other than the given abbreviations will display the message: Unknown
The output is attached as screen shot.
