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lukranit [14]
3 years ago
6

Solve for x 2/7x = 6 (SHOW YOUR WORK)

Mathematics
2 answers:
castortr0y [4]3 years ago
5 0

Answer:

The answer to your question is  x = 21

Step-by-step explanation:

Equation

                                       \frac{2}{7} x = 6

- Multiply both sides by 7

                                        \frac{(2)(7)x}{7} = 6(7)

- Simplify

                                        2x = 42

- Divide both sides by 2

                                         \frac{2x}{2} = \frac{42}{2}

- Simplify

                                         x = 21

Illusion [34]3 years ago
5 0

Answer:

x=21

Step-by-step explanation:

\frac{2}{7} x=6

Multiply both sides by 7:

2x=42

Divide both sides by 2:

x=21

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Answer:

1/5

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3 years ago
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what is the missing number? imput B;4,12,16,24,32,40. output A:8,16,20,_,_ rules a=b+4. SUPER URGENT !!!!!!!!!!
BigorU [14]
The given equations is: a=b+4
Given the following clues:
a=24+4 --- 28
a=32+4 --- 36
a= 40+4 --- 44

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3 years ago
Find the missing measure in the triangle below.
denis23 [38]

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Step-by-step explanation:

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7 0
3 years ago
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What is the remainder of f(x)=x^4-2x^3-27x^2-9x+18 when divided by binomial x+4
givi [52]

Answer:

The remainder will be 6.

Step-by-step explanation:

We have the function:

f(x)=x^4-2x^3-27x^2-9x+18

And we want to find the remainder after it is divided by the binomial:

x+4

We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (<em>x</em> - <em>a</em>), then the remainder will be given by P(a).

Here, our divisor is (<em>x</em> + 4). We can rewrite this as (<em>x</em> - (-4)).

Therefore, <em>a</em> = -4.

Then according to the PRT, the remainder will be:

f(-4)=(-4)^4-2(-4)^3-27(-4)^2-9(-4)+18=6

The remainder will be 6.

4 0
2 years ago
Help quick please!!
Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0
3 years ago
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