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tatyana61 [14]
3 years ago
14

Can you prove that DEF = HGF.!? Justify your answer.

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Step-by-step explanation:

In  \: \triangle DEF  \: \&  \: \triangle HGF  \\ EF \:  \cong \:  GF...(given)  \\  \angle EFD \cong  \angle GFH \\ (vertically \: opposite \: angles) \\ \ DF \:  \cong \:  HF...(given) \\   \therefore \: \triangle DEF  \cong \triangle HGF \\ (By\: SAS \:criterion\: of \:congruence)

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Step-by-step explanation:

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Now , the required probability:

P(J∪M∪H) = P(J) + P(M)  + P(H) - P(J∩M) - P(J∩H) - P(M∩H)+ P(J∩M∩H)

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3 years ago
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