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tatyana61 [14]
3 years ago
14

Can you prove that DEF = HGF.!? Justify your answer.

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Step-by-step explanation:

In  \: \triangle DEF  \: \&  \: \triangle HGF  \\ EF \:  \cong \:  GF...(given)  \\  \angle EFD \cong  \angle GFH \\ (vertically \: opposite \: angles) \\ \ DF \:  \cong \:  HF...(given) \\   \therefore \: \triangle DEF  \cong \triangle HGF \\ (By\: SAS \:criterion\: of \:congruence)

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DO IT ASAP! Thank you very much!
frozen [14]

Answer:

a = 5

Step-by-step explanation:

According to the factor theorem, if x + 2 is a factor, then by dividing the polynomial by the binomial, we are meant not to have a remainder

In this case, the remainder would be zero

So, if we set the binomial equals zero and substitute the x-value into the polynomial, we are supposed to have 0

So we have this as;

x + 2 = 0

x = -2

-2^3 -2(-2)^2 -2(a) + 6 = 0

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3 years ago
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Answer:

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Step-by-step explanation:

Put the value of the variable where the variable is in the expression and do the arithmetic.

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inysia [295]

Answer:

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Step-by-step explanation:

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