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tatyana61 [14]
3 years ago
14

Can you prove that DEF = HGF.!? Justify your answer.

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Step-by-step explanation:

In  \: \triangle DEF  \: \&  \: \triangle HGF  \\ EF \:  \cong \:  GF...(given)  \\  \angle EFD \cong  \angle GFH \\ (vertically \: opposite \: angles) \\ \ DF \:  \cong \:  HF...(given) \\   \therefore \: \triangle DEF  \cong \triangle HGF \\ (By\: SAS \:criterion\: of \:congruence)

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5 more than the quotient of a number and 8 is 42
Zepler [3.9K]

Answer:

<u>The number is 296.</u>

Step-by-step explanation:

Let's call "x" to the number we are looking for.

Now, the problem states that "5 more than the quotient of a number and 8 is 42". This means that this number is being divided by 8, it's also being additioned 5 and the final result is 42. Therefore, the expression of this operations on this number is the following:

\frac{x}{8}+5=42. Let's solve the equation to find x.

1. Write the expression.

\frac{x}{8}+5=42

2. Substract 5 from both sides and simplify.

\frac{x}{8}+5-5=42-5\\\\\frac{x}{8}=37\\\\

3. Multiply 8 on both sides and simplify.

8*\frac{x}{8}=37*8\\\\x=296

<u>We have found our number, it's 296!</u>

3 0
2 years ago
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What is the next number in the sequence? 9….16….24….33…
Delvig [45]
43 ........................................
3 0
3 years ago
4 times a number plus 16 is more than 28.
umka21 [38]
4*4= 16 + 16= 32 :) You could do 4 * 4 that equals 16 then add 16 to that to get over 28.
4 0
4 years ago
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3(5j+2)=2(3j-6) how do i do this
ohaa [14]

3(5j+2)=2(3j-6) do distributed to remove parenthesis  15j+6=6j-3 . Then move all j to left side and the second term to right side 15j-6j=-3-6. Now solve both sides  9j= -9. Now divide both sides by 9 to get j alone to j =  -1

5 0
3 years ago
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Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your
Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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4 0
1 year ago
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