Answer:
Scalene
Explanation:
It isn’t equilateral or isosceles. Therefore it must be scalene
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
Set tay equal to x, and set Omar to be equal to y. Then solve for x, which is done simply by dividing both sides by the y value. The answer is your slope
<span>a. y = x^2 – 81 is a quadratic function.
According to the definition:
A quadratic function is defined as a function with the maximum coefficient of 2.Only first option has a coefficient of 2 and the rest have not.</span>
D. 150 should be your answer.
