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2 years ago

7

The approximate number of bicycles in the United States in the year 2007 was 14,000,000. How can this number be expressed in sci

entific notation?

1 answer:

elena-s [515]2 years ago

8 0

Answer:

$1.4*10^7$

Step-by-step explanation:

we have

$14,000,000$

Remember that

$14,000,000=1.4(10,000,000)$

and

$10,000,000=1*10^7=10^7$

substitute

$14,000,000=1.4*10^7$

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Harold has 4 classes each morning. Each class is 1 hour long, and there are 10 minutes between classes. The first class is at 8

Viktor [21]

The fourth class ends at 12:30 pm

<em><u>Solution:</u></em>

Given that Harold has 4 classes each morning

Each class is 1 hour long, and there are 10 minutes between classes

The first class is at 8 A.M

<em><u>To find: Time at which fourth class ends</u></em>

Since each is 1 hour long and 10 minutes gap between classes

First class = 8 A.M to 9 A.M

Second class = 9:10 A.M to 10 : 10 AM

Third class = 10 : 20 AM to 11 : 20 AM

Fourth class = 11 : 30 AM to 12 : 30 PM

Thus the fourth class ends at 12:30 pm

4 0

2 years ago

A dog starts walking, slows down,

Tomtit [17]

Answer:

You would draw a sloped line leaning to the right, then make it less steep, then draw a flat line.

Explanation:

The steeper slope represents the dog walking at a normal pace, when the line gets a little less steep it means the dog has slowed down, and when it is flat is where ethe dog took a rest.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

7 0

2 years ago

7(x−5)−9=334 what is the answer of x

slega [8]

Answer:

$\boxed {x = 54}$

Step-by-step explanation:

Solve for the value of $x$ :

$7(x - 5) - 9 = 334$

-Use <u>Distributive Property</u>:

$7(x - 5) - 9 = 334$

$7x - 35 - 9 = 334$

-Combine like terms:

$7x - 35 - 9 = 334$

$7x - 44 = 334$

-Add both sides by $44$ :

$7x - 44 + 44 = 334 + 44$

$7x = 378$

-Divide both sides by $7$ :

$\frac{7x}{7}= \frac{378}{7}$

$\boxed {x = 54}$

Therefore, the value of $x$ is $54$ .

8 0

3 years ago

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0

2 years ago

Answer the question below in the image

Goryan [66]

Answer:

D

Step-by-step explanation:

7 0

2 years ago