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Marianna [84]
3 years ago
6

joshua carried 52 loads of sand to make a play area. each load weighed 21 pounds. how many pounds od sand does joshua use to mak

e the play area? use the numbers and symbols on the keypad to write expression needed to solve problem. then solve the problem.
Mathematics
2 answers:
lukranit [14]3 years ago
8 0
1092 pounds !!!!!!!!!!
Mashcka [7]3 years ago
6 0
52 loads of 21 pound sand. The equation would be 52 times 21 and the answer is 1092.
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Solve for x.<br> 10x – 79 = 2x + 49<br> x = [?]
Harrizon [31]

Answer:

x = 16

Step-by-step explanation:

<u>Step 1:  Add 79 to both sides</u>

10x - 79 + 79 = 2x + 49 + 79

10x = 2x + 128

<u>Step 2:  Subtract 2x from both sides</u>

10x - 2x = 2x - 2x + 128

8x = 128

<u>Step 3:  Divide 8 from both sides</u>

\frac{8x}{8} = \frac{128}{8}

x = 16

Answer:  x = 16

7 0
3 years ago
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6x2-18x-60= What is the answer to the question
TiliK225 [7]

Answer:

1092

Step-by-step explanation:

7 0
3 years ago
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What is the ratio in which the point P(3/4,5/12) decides the line segment joining points A(1/2,3/2) and B(2,-5)
timama [110]

Given:

The point P\left(\dfrac{3}{4},\dfrac{5}{12}\right) divides the line segment joining points A\left(\dfrac{1}{2},\dfrac{3}{2}\right) and B(2,-5).

To find:

The ratio in which he point P divides the segment AB.

Solution:

Section formula: If a point divides a segment in m:n, then the coordinates of that point are,

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Let point P divides the segment AB in m:n. Then by using the section formula, we get

\left(\dfrac{3}{4},\dfrac{5}{12}\right)=\left(\dfrac{m(2)+n(\dfrac{1}{2})}{m+n},\dfrac{m(-5)+n(\dfrac{3}{2})}{m+n}\right)

\left(\dfrac{3}{4},\dfrac{5}{12}\right)=\left(\dfrac{2m+\dfrac{n}{2}}{m+n},\dfrac{-5m+\dfrac{3n}{2}}{m+n}\right)

On comparing both sides, we get

\dfrac{3}{4}=\dfrac{2m+\dfrac{n}{2}}{m+n}

\dfrac{3}{4}(m+n)=\dfrac{4m+n}{2}

Multiply both sides by 4.

3(m+n)=2(4m+n)

3m+3n=8m+2n

3n-2n=8m-3m

n=5m

It can be written as

\dfrac{1}{5}=\dfrac{m}{n}

1:5=m:n

Therefore, the point P divides the line segment AB in 1:5.

6 0
3 years ago
How do you find the perimeter of a trapezoid?
AlexFokin [52]
Add the lengths of all sides 
3 0
3 years ago
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If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH
olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

\angle EFG=\angle EFH+\angle HFG

18x+11=(5x+1)+(62)

18x+11=5x+63

Isolate variable terms.

18x-5x=63-11

13x=52

Divide both sides by 13.

x=\dfrac{52}{13}

x=4

The value of x is 4.

\angle EFH=(5x+1)^\circ

\angle EFH=(5(4)+1)^\circ

\angle EFH=(20+1)^\circ

\angle EFH=21^\circ

Therefore, the measure of ∠EFH is 21°.

8 0
3 years ago
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