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Korvikt [17]
3 years ago
11

25 POINTS PLEASE HELPPP TYYY !!

Mathematics
2 answers:
Anni [7]3 years ago
5 0
The answer is -1/4 I think
umka2103 [35]3 years ago
3 0
C= -1/4 hope it helps :D
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Can someone please help me !!!
andreyandreev [35.5K]
1) false
2) t is the independant variable, C is the dependant variable
3) true
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3 years ago
The student government-collected data on club membership by grade level. Data on club membership are summarized in the table sho
Musya8 [376]

Answer:

d.yes because P(Grade 12/PClub Membership) = P(Grade 12)

Step-by-step explanation:

8 0
4 years ago
16:14:34
azamat

Answer:

C

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 3 and (a, b) = (2, - \frac{1}{2} ) , thus

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5 0
3 years ago
Read 2 more answers
Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.
kaheart [24]
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------

\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
\\\\\\
\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
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3 0
3 years ago
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Two random samples of 40 students were drawn independently from two populations of students. Assume their aptitude tests are nor
dybincka [34]

Answer:

b. Do not reject the null hypothesis

Step-by-step explanation:

Given that two random samples of 40 students were drawn independently from two populations of students.  Assuming equal variances

we have the following data.

Sample 1

Mean:  

76

 

Standard deviation:  

8

 

Sample size:  

40

 

Sample 2

Mean:  

73

 

Standard deviation:  

7

 

Sample size:  

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H_0: \bar x_1=\bar x_2\\H_a:  \bar x_1\neq \bar x_2

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Standard error 1.681

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Since p value >0.05,

b. Do not reject the null hypothesis

7 0
4 years ago
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