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eimsori [14]
4 years ago
5

Find all the zeros of f(x)=2x4-5x3-x2-5x-3

Mathematics
1 answer:
enot [183]4 years ago
7 0
I really dont understand what this one means either so if someone could explain that because all that i see is no 0's so explain that to me and I will add you as a friend and thank you once again but to everyone that sees this have a nice and enjoyable summer!!!!!!!!!!
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Carlita will visit 14 cities
Tanya [424]

Answer:

$52091.95

Step-by-step explanation:

From the given information:

The number of  cities visited = 14

Cost of each cooking demonstration = $3450

The total cost of cooking demonstration = $3450 × 14

= $48300

Book signing material = $1475

∴

The total cost of cooking demonstration and book material is:

= $48300 + $1475 = $49775 ---- (i)

Total meter traveled in visiting 14 cities = 240 * 13 = 3120 miles

However; suppose the weekly rental fee fine = $x  &

the change per mile = $y

Then

y*540 + x = 1188.15    --- (ii)

y*880 + x = 1310.55   --- (iii)

From equation (ii) and (iii)

y *340 = 122.4

y = 122.4/340

y = 0.36

From (ii)

y × 540 + x = 1188.15

(0.36)540 + x = 1188.15

x = 1188.15 - (0.36)540

x = 993.75

Hence, the total cost of travelling by RV camper = $1993.75 + 3120 × (0.36)

= $2116.95

Thus, the total amount the publisher should budget = $49975.0 + $2116.95

= $52091.95

8 0
3 years ago
Please help me on this. you need to match the terms to the correct number.
Gnom [1K]

Answer:

64=8

49=7

36=6

25=5

100=10

16=4

9=3

20=4.5

4=2

1=1

67=8.2

81=9

5 0
3 years ago
Jon and Anne had an equal amount of money. Jon spent $10. Anne spent $30. Now Jon has twice as much money as Anne. How much did
bulgar [2K]
They would have had $50 at the beginning
8 0
3 years ago
if alpha and beta are zeroes of polynomial 4x^2-1 obtain a quadratic polynomial whose zeroes are 1/2 alpha+beta and 1/alpha+2 be
AysviL [449]
Ok so 4x2-1 gives us 3
4 0
3 years ago
Use the lim f(x)-f(a)/x-a to find the derivative.
Tresset [83]
Hello,

f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)

lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11

Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11



at point(1,-7)

4 0
3 years ago
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