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Alekssandra [29.7K]
3 years ago
15

Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\
5=\sqrt{(-1-2)^2+(-2-y_1)^2}\\
\sqrt{9+4+4y_1+y_1^2}=5\\
y_1^2+4y_1+13=25\\
y_1^2+4y_1-12=0\\
y_1^2+6y_1-2y_1-12=0\\
y_1(y_1+6)-2(y_1+6)=0\\
(y_1-2)(y_1+6)=0\\
y_1=2 \vee y_1=-6\\\\
\boxed{(2,2),(-6,2)}


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-BARSIC- [3]

z = 37°

Step-by-step explanation:

The exterior angle theorem says that the sum of two internal angles is equal to the exterior angle

In this case the sum of z and z+4 will be equal to z+41

Writing mathematically

z + z+ 4 = z + 41\\2z+4 = z + 41\\2z -z = 41 -4\\z = 37

Hence

z = 37°

Keywords: Angles, Triangles

Learn more about angles at:

  • brainly.com/question/10800566
  • brainly.com/question/10808021

#LearnwithBrainly

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It wouldn't affect the mean or the median.

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A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb
Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700

Solving the linear system above:

(0.55 *S +0.59*G)- \frac{0.55}{0.45} (0.45*S+0.41*G)= 2,300-\frac{0.55}{0.45}*1,700*\\0.088888*G = 222.222\\G=2,500\\S =\frac{2,300-2,500*0.59}{0.55}\\S=1500

2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

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3 years ago
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Answer:

y=3x-2

Step-by-step explanation:

Because the equation for slope intercept form is y=mx+b!

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3 years ago
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Answer:

140,620,000

Step-by-step explanation:

There are two types of standard form. The one above (given to you) is the normal standard form. However, there is another one. This one would look like:

140,620,000 = 1.4062 x 10^8

Remember that in this standard form, you must move the decimal to just after the first place value, and the amount of moves you made for the decimal is the amount in the power over 10.

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6 0
3 years ago
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