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gogolik [260]
3 years ago
15

Weights of babies at the local community hospital have a distribution that is approximately normal with a mean weight of 7.43 po

unds and a standard deviation of 1.25 pounds. A premature baby can be classified as being less than 5.51 pounds. A. Find the probability of a randomly selected baby weighing less than 5.51 pounds. B. If 25 babies are randomly selected, what is the probability that their weight will be less than 5.51 pounds?

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

Step-by-step explanation:

Hope this helped

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A bank is experimenting with programs to direct bill companies for commercial loans. They are particularly interested in the num
Evgesh-ka [11]

Answer:

The 95% confidence interval for true mean error is (4.57, 4.63).

Step-by-step explanation:

Let <em>X</em> = the number of errors of a billing program.

According to the Central limit theorem if a large sample (<em>n</em> > 30) is drawn from an unknown population then the sampling distribution of the sample mean will follow a Normal distribution with mean (\mu_{\bar x}=\mu) and standard deviation      (\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}).

The sample size of the loans is, <em>n</em> = 1000.

The mean is, {\bar x}=4.6.

The standard deviation is,  \sigma_{\bar x}=\frac{0.50}{\sqrt{1000}}=0.016

The confidence interval for mean is:

CI=\bar x\pm z_{\alpha /2}\times \sigma_{\bar x}

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha /2}=z_{0.05/2}=z_{0.025}=1.96

**Use the <em>z</em>-table for critical values.

Compute the 95% confidence interval for true mean error as follows:

CI=\bar x\pm z_{\alpha /2}\times \sigma_{\bar x}\\=4.6\pm1.96\times0.016\\=4.6\pm0.03136\\=(4.56864, 4.63136)\\\approx(4.57, 4.63)

Thus, the 95% confidence interval for true mean error is (4.57, 4.63).

7 0
3 years ago
Read 2 more answers
Write the equation of the line on the graph below.
irakobra [83]

Answer:

what do you mean?

Step-by-step explanation:

5 0
3 years ago
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A box contains 14 large marbles and 11 small marbles. Each marble is either green or white. 8 of the large marbles are green, an
prisoha [69]

Answer:

Step-by-step explanation:

Given that:

Number of Large Marbles = 14

Number of Small Marbles = 11

Number of Green large marbles = 8

Number of White small marbles = 5

We can now find the number of white large marbles and green small marbles from the information stated above.

No of white large marble = total large marble minus green large marble

= 14-8

= 6

No of green small marbles = Total small marbles minus white small marble.

= 11-5

= 6

Let the following be represented

( X,Y, Z,Q ) as follows:

Let Y be the event of drawing small marble

Let X be the event of drawing large marble

Let Q be the event of drawing white marble

Let Z be the event of drawing green marble.

Since, only one marble is drawn at a time we calculate,

P( X ) = 14/25

P( Y) = 11/25

P(Z) = 14/25

P( Q) = 11/25

P(Y∪Q)=P(Y)+P(Z)−P(Y∩Z)...(1)

We need to find the value of

P(Y∩Z)

In 11 small marbles there are 6 green marbles so the value of P(Y∩Z) is given by P(Y∩Z)=6/11

Therefore, substitute the values in equation 1.

P(Y∪Z)=P(Y)+P(Z)−P(Y∩Z)=11/25+14/25-

6/11

=0.44+0.56−0.5455

= 1-0.5455

= 909/2000

= 0.4545

Then, one can conclude that the probability of drawing a small or green marble is 0.4545

4 0
3 years ago
Todd begins piano practice at 4:15 P.M. and ends at 5:50 P.M. How long does he practice?
marta [7]
If He began at 4:15 and ended at 5:50 then that would be 95 minutes
7 0
3 years ago
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7. Find the sum or difference.<br> -2(d +1) + (6d +4)
Arturiano [62]

Answer:

Step-by-step explanation:

Sum

-2d + 1 + 6d + 4

Solving like terms

4d + 5

Difference

-2d + 1 - 6d - 4

-8d - 3

4 0
3 years ago
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