In a geometric sequence, the numbers are found by multiplying each number by a fixed amount called a common ratio(r).
a1....this is ur first number....so since a1 = 3, ur first number is 3...and to find ur next numbers, multiply each number by r, the common ratio (which equals 0.5)
first number = 3.......3 x 0.5 = 1.5
second number = 1.5......1.5 x 0.5 = 0.75
third number = 0.75
si the first 3 terms are : 3, 1.5, 0.75
If you factor the denominator of the left multiplicand...
[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:
(a+3)/a
now you have
(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:
1/a * 2a^3/(a-1) which is:
2a^3/(a(a-1)) so now a^1 cancel leaving
2a^2/(a-1)
N+3/4 = 1/4
n = 1/4 - 3/4
= -2/4
= -1/2
Hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =2 and b = -5 (Center at the A) and: r = 12
</span></span>the equation of the circle is : (x-2)² +(y+5)² = 12²=144 (answer d)
Answer:
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Step-by-step explanation: