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3 years ago

Three sticks of butter are needed for every 24 cookies.

Mathematics

1 answer:

NeX [460]3 years ago

3 0

Answer:

40 cookies

Step-by-step explanation:

24÷3=8

8×5=40

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Amina was asked to write the prime factorization of 525

ioda

Answer:

Prime factorization of 525 is 3×5×5×7

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3 years ago

Read 2 more answers

I try to look this up and people said yes or no I just need a straight answer

Anna11 [10]

start inside the square root, replace X with -7.

-7 + 11 = 4

The number 4 comes out of the square root as 2.

Now there's a minus factor out there. Let's multiply this negative factor by 2 and get -2.

Now let's add -2 and -3.

Our output is -5.

3 0

2 years ago

6. Meg measured the length of some pieces

alexandr1967 [171]

Answer:

longest length minus the shortest

Step-by-step explanation:

8 0

3 years ago

9) Let<br> X-2, x, x+3 <br> be the first 3 terms of a geometric sequence. FInd the value of x..

Reil [10]

Hello,

Let's r the ration

We suppose x ≠0

x=r*(x-2)==>r=x/(x-2)

x+3=r*x==> (x+3)/x=x/(x-2)==>(x+3)(x-2)=x²
==>x²+3x-2x-6=x² ==>x-6=0==>x=6

x-2=6-4=4
x=6
x+3=6+3=9
6=4*3/2
9=6*3/2

Ration 3/2
First term: 4

7 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago