Bugs with shorter bills had more access to sustenance, enabling them to deliver all the more posterity. Bugs that happened to have short breaks were better ready to feast upon the little organic products. Their expanded access to nourishment enabled them to deliver all the more posterity, which likewise had little snouts. In any case, bugs with little bills did not emerge so as to feast upon the little natural products. Transformative change comes to fruition as the extent of people in the populace showing a specific characteristic increments from age to age. The characteristic does not change step by step in all individuals from the populace.
A ribosome is the part of a cell is used by a virus to produce its protective
protein coat.
Virus produces a protective protein coat known as capsids which serves as
a means of protection for the organism. The capsids are produced through
the organelle known as ribosome.,
The ribosome acts as a site for protein synthesis in organisms and the
capsids being made up of protein means the ribosome was used to
produce its protective protein coat.
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Answer:
A taxonomy map of philosophy is created using 5 layer version
Explanation:
The map is drawn in a circular form, the parent is usually the center and then the child or the sub branches are then made around the first- parent circle to show the relation between the parent and its child. These branches can have their own sub branches which are then included around the branches the child of the original parent.
Answer:
Phagocytosis refers to the engulfing of larger, solid particles. Often, the engulfed particle is another cell, like when a white blood cell, which is a part of the immune system, engulfs a bacterium to destroy it.
Answer: the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Explanation:
We know that; Gram negative bacteria looks pale reddish in color under a light microscope from Gram staining.
therefore
There are 30 red bacterial colonies counted.
1 mL of from tube 1 was removed and added to tube with 99 mL saline (tube 2) dilution is 1/100.
transferred volume into the plate is 1 mL.
Now, we have to determine the cfu/g Gram-negative bacteria in the fecal sample
Formula to calculate CFU/g bacteria in fecal sample is expressed as;
C = n/(s×d )
where C is concentration (CFU/g)
, n is number of colonies
, s is volume transferred to plate
, d is dilution factor.
so we substitute
C = 30 / ((1/100) × 1)
C = 30 / 0.01
C = 3000
C = 3.0 × 10^3
THERFERE, the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
