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aleksklad [387]
3 years ago
9

A rapid method of speciation that has been important in the history of flowering plants is

Biology
2 answers:
Margarita [4]3 years ago
8 0

Answer:

Polyploidy

Explanation:

Polyploidy can be defined as a rapid method of speciation that has been important in the history of flowering plants.

In plants, it involves the possession of two complete sets of chromosomes and it leads to the origin of new species.

Hence, the two sets of chromosomes comprises of triploidy (69 chromosomes) and tetraploidy (92 chromosomes).

labwork [276]3 years ago
3 0

Answer:

behavioral isolation

Explanation:

Speciation  can be explained as a situation when a group within a species separates from other members of its species and develops its own unique characteristics. It can also be described as an evolutionary process by which populations evolve to become distinct species. This means that , through this process a new kind of plant or animal species is created.

The things that were known to be cause of speciation are rivers change course, mountains rise, continents drift and organisms migration.

Behavioral isolation can be described as a barrier that prevents interbreeding between closely related species because there is no mate recognition between females and males of the different species. This means the development of different behaviors that are not recognized or preferred by members in another population.

In this case, behavioral isolation has been the major driver of speciation in flowering plants ,and has been the mechanism that ensure the production of viable offspring.

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Brainliest Are dolphins mammals A. yes B.no C. i dunno
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You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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