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Tasya [4]
4 years ago
14

What are the solutions of the equation?

Mathematics
2 answers:
fredd [130]4 years ago
8 0

For this case, we have the following quadratic equation:

16x ^ 2 + 24x + 5 = 5\\16x ^ 2 + 24x + 5-5 = 0\\16x ^ 2 + 24x = 0

If we divide between 4 on both sides to simplify we have:

4x ^ 2 + 6x = 0

 This equation is of the form:

ax ^ 2 + bx + c = 0

Where:

a = 4\\b = 6\\c = 0

Its roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\x = \frac {-6 \pm \sqrt {6 ^ 2-4 (4) (0)}} {2 (4)}\\x = \frac {-6 \pm \sqrt {36}} {8}\\x = \frac {-6 \pm6} {8}

So, we have two roots:

x_ {1} = \frac {-6 + 6} {8} = 0\\x_ {2} = \frac {-6-6} {8} = - \frac {12} {8} = - \frac {3} {2}

Answer:

The roots are:x_ {1} = 0\ and\ x_ {2} = - \frac {3} {2}

None of the options given are solution

yuradex [85]4 years ago
4 0

Answer:

B

Step-by-step explanation:

you have the wrong equation posted.

if you meant to post 16x^2+24x+5=0

the answer would be B.


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Answer:

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Step-by-step explanation:

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For Substance B:

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{M=300(0.9985)^t

{M=500(0.9963)^t

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