Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.

7 0

3 years ago

If y varies inversely as x and y=24 when x=8, find y when x is 4

olga2289 [7]

Y would equal 12 if x were to equal 4. You can think of it as a proportion.

6 0

4 years ago

Last Sunday 1.575 people visited the amusement park % of the visitors were adults , 16% were teenagers and 28 were children ages

jasenka [17]

Answer:

882 , 252 , 441

Step-by-step explanation:

There are some mistakes in question and the corrected one is written below:

Q. Last Sunday 1,575 people visited the amusement park. 56% of the visitors were adults, 16% were teenagers, and 28% were children ages 12 and under. Find the number of adults, teenagers, and children that visited the park.

Given:

Total number of people visited amusement park = 1,575

Percent of adult people = 56%

Percent of teenagers = 16%

Percent of children = 28%

Now, we have to find number of adults, teenagers, and children that visited the park last Sunday.

Solution:

Number of adults = $56\%\ of \ 1575=\frac{56}{100}\times1575= \frac{88200}{100} =882\ adults$

Number of teenagers = $16\%\ of\ 1575=\frac{16}{100} \times1575=\frac{25200}{100} =252\ teenagers$

Number of children = $28\%\ of\ 1575=\frac{28}{100} \times1575=\frac{44100}{100} =441\ children$

Therefore, the number of adults are 882 , teenagers are 252 , and children are 441 that visited the park last Sunday.

6 0

3 years ago

What is the LCD of 8/9 and 2/3

Charra [1.4K]

9 is the least common denominator

7 0

2 years ago

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