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Brums [2.3K]
3 years ago
9

What’s the least common multiple of x^2-2x-15 and x^2+2x-3?

Mathematics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

\large\boxed{LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)}\\\boxed{=x^3-3x^2-13x+15}

Step-by-step explanation:

x^2-2x-15=x^2+3x-5x-15=x(x+3)-5(x+3)=(x+3)(x-5)\\\\\\x^2+2x-3=x^2+3x-1x-3=x(x+3)-1(x+3)=(x+3)(x-1)\\\\LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)\\\\=(x^2-2x-15)(x-1)\qquad\text{use FOIL}\\\\=(x^2)(x)+(x^2)(-1)+(-2x)(x)+(-2x)(-1)+(-15)(x)+(-15)(-1)\\\\=x^3-x^2-2x^2+2x-15x+15\qquad\text{combine like terms}\\\\=x^3+(-x^2-2x^2)+(2x-15x)+15\\\\=x^3-3x^2-13x+15

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Alan says that the distance from Hadley to Greenville is 16 miles. Is he correct?Explain
yuradex [85]

Answer:

Step-by-step explanation:

Considering the complete question attached in figure.

Consider

Hadley = x

Parker = y

Greenville = z

Distance between Greenville and Parker = yz = 29

Given that distance between Hadley and Greenville is 13 miles less than the distance between Parker and Greenville.

                                        xz = yz -13 --- (1)

Distance between hardley and greenville = xz  = ?

From (1)

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3 years ago
Adjacent angles and linear pairs can you help?
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Answer:

Step-by-step explanation:

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