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4 years ago

Find the slope of the line that contains the following points. R(-3,5), S(3,-2)

Mathematics

2 answers:

sesenic [268]4 years ago

6 0

Answer:

This can be solved using the slope formula.

(y2 - y1) / (x2 - x1) = m

m is the meaning of slope

Answer: m= -7/6

Step-by-step explanation:

Goryan [66]4 years ago

4 0

Answer:

-7/6

Step-by-step explanation:

var y/ var x

5 to -2 is variation y ----> -7

-3 to 3 is variation x ---> 6

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a rectangular field is 45 feet wide and is enclosed by 210 feet of fencing what is the area of the field in square feet

Helen [10]

Find the length of the field first. To do this, write a formula for the perimeter, P, of the field: P = 210 ft = 2(45 ft) + 2L.

Then 2L = 210 - 90 = 120, and L = 60 (feet).

The area of the field is thus WL = (45 ft)(60 ft) = 2700 sq ft

7 0

3 years ago

A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 0.499, \sigma = 0.002$

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.504 - 0.494}{0.002}$

$Z = 2.5$

$Z = 2.5$ has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.496 - 0.494}{0.002}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0

4 years ago

if 5000000 invested at 4% interest compounded continuously how much will the investment be worth in 30 years

umka21 [38]

For this you use A=Pe^(rt)
A=furutre amount
P=present amount
e=natural base
r=rate in decimal
t=times in years

A=?
P=5000000
r=0.04
t=30

A=5,000,000e^(0.04*30)
A=5,000,000e^(1.2)
A=16600584.613683

8 0

3 years ago

Read 2 more answers

Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t

Viefleur [7K]

Each term differs by -68 and the first term is -68, we have:

$a_{n}=a_1-68(n-1) \implies \\ a_{n}=a_1-68n+68 \implies\\ a_n=-68-68n+68 \implies \\ a_n=-68n$