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stepan [7]
3 years ago
11

(Picture Provided) A line passes through the points

Mathematics
2 answers:
faust18 [17]3 years ago
8 0
Only the top one is yes other 3 are no
muminat3 years ago
3 0

Given that : A line passes through the points (6,5) and (2,2).

We need to select the forms of linear equations given:

First we need to find the slope between (6,5) and (2,2) points first.

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{2-5}{2-6} =\frac{3}{4}

So, we got slope of the equation: 3/4.

Taking point (6,5) and slope 3/4.

Using point -slope form y-y1 =m(x-x1), we get

<h3>y-5 = 3/4 (x-6).</h3>

Taking point (2,2)  and slope 3/4, we get

<h3>y-2 = 3/4 (x-2).</h3><h3>Therefore, correct options are First and Fourth options.</h3><h3 />

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Answer:

1325/10000

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How to solve:
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7 0
4 years ago
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The following data was collected from the manufacturing of an auto component. It represents the diameter (in mm) of that compone
kari74 [83]

Answer:

14.6

Step-by-step explanation:

(A). STEP ONE: Calculate the mean

(1). Row one = (10 + 12 + 12 + 14 ) = 48/4 = 12.

(2). Row Two: (12 + 11 + 13 + 16 ) = 52/4 = 13.

(3). Row three : (11 + 13 + 14 + 14)/4 = 13.

(4). Row four: (11 + 10 + 7 + 8)/4 = 36/4 = 9.

(5). Row five: (13 +12 + 14 + 13)/4 = 52/4 = 13.

(B). STEP TWO:

- determine the maximum and minimum value for each row.

- for each row, maximum - minimum.

Maximum values for each row:

Row one = 14, row two= 16, row three = 14, row four = 11 and row five = 14.

Minimum value for each row:

Row one = 10, row two = 11, row three = 11, row four =7 and row five = 12.

DIFFERENCES in each row :

row one = 14 - 10 = 4, row two = 16 - 11 = 5, row three = 14 - 11 = 3, row four = 11 - 7 = 4 and row five = 14 -12 = 2.

(C). STEP THREE: Calculate the mean of all the rows = 60/5 = 12.

(D). STEP FOUR : Calculate the Average Range = 18/5 = 3.6.

(E). STEP FIVE : Calculate the UCL.

A = Average rage × 0.729 = 3.6 × 0.729.

B = overall mean = 12.

UCL = A + B = 14.6.

7 0
3 years ago
Name a pair of perpendicular lines: <br>is line BC and AJ perpendicular: explain ​
wel
A pair of perpendicular lines would be line CF and line AJ.

Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
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3 years ago
At what points does the helix r(t) = sin t, cos t, t intersect the sphere x2 + y2 + z2 = 65? (round your answers to three decima
Firdavs [7]
\mathbf r(t)=\langle x(t),y(t),z(t)\rangle=\langle\sin t,\cos t,t\rangle

x^2+y^2+z^2=\sin^2t+\cos^2t+t^2=65
\implies t^2=64
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