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anzhelika [568]
3 years ago
5

(16 divided by 4) x (7-4)

Mathematics
2 answers:
hram777 [196]3 years ago
6 0
The answer is 12, because 16 divided by 4 is 4 and 7-4 is 3 so 3 times 4 is 12.
zavuch27 [327]3 years ago
4 0
4 x 3 = 12
12 would be the answer
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What is another way to name ∠MNO ?
Serhud [2]
ONM
OMN
NMO
Hope that helped!
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3 years ago
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Zoologists are studying two newly discovered species of insects in a previously unexplored section of rain forest. They estimate
salantis [7]
The population Pa of insect A after t years is given by the equation 
     Pa = 1.3(1-0.038)^t 
while the population Pb of insect B after t years is 
     Pb = 2.1(1-0.046)^t

We equate the above expressions to find the number of years t it will take the two populations to be equal: 
     Pa = Pb
     1.3(1-0.038)^t  = 2.1(1-0.046)^t
     1.3(0.962)^t  = 2.1(0.954)^t
These are the equations that can be used to determine how long it will be before the populations of the two species are equal.

We can now solve for t:
     (0.962)^t / (0.954)^t = 2.1/1.3
     (0.962/0.954)^t = 2.1/1.3
After taking the log of both sides of our equation, number of years t is
     t = log (2.1/1.3) / log (0.962/0.954)
     t = 57 years
Therefore, it will take 57 years for the population of insect A to equal the population of insect B.
8 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs.
Alborosie

2⁻³² = (-2²)⁻⁶ • (2⁻⁵)⁻⁴

2⁻⁵ = (2²)² • (2³)⁻³

2⁸ = (-2⁻⁴)⁻² • (2²)⁰

1 = 2⁴ • (2²)⁻²

6 0
2 years ago
Please help me. This is real confusing. ​
katrin2010 [14]

Answer:

1st problem: b) A=2500(1.01)^{12t}

2nd problem:  c) A=2500e^{.12t}

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

A=P(1+\frac{r}{n})^{nt}

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

A=2500(1+\frac{.12}{12})^{12t}

Time to clean up the inside of the ( ).

A=2500(1+.01)^{12t}

A=2500(1.01)^{12t}

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

A=Pe^{rt}

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

A=2500e^{.12t}.

6 0
3 years ago
Find the midpoint of the segment between (6,7) and (6,-5)
Norma-Jean [14]

Answer:

(6,1)

Step-by-step explanation:

midpoint = ((x2+x1),(y2+y1)/2)

= (6+6)/2, (-5+7)/2

= 12/2, 2/2

= 6,1

3 0
3 years ago
Read 2 more answers
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