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3 years ago

a recipe for pasta. makes enough for eight servings. how many servings can be made using 4/8 of each ingredient in the recipe?

2 answers:

6 0

Since the recipe makes 8 servings, we can use this information .
4/8 reduces down to 1/2, so based on that information, if we used half of the ingredients, we would have half the servings,
Therefore the recipe makes 4 servings.

Let me know if you don't understand! I hope this helped!

Inga [223]3 years ago

3 0

4 servings bro. Not much XD

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Twenty-four students took a test. Fourteen students earned an A and 10 students earned a

horrorfan [7]

Total number of students who did a test was 24
Number of students who scored an A is 14
Number of students who scored a B is 10
Probability that when we randomly select a student, he/she will have an A is:
(Number of students that scored A)/(Total number of students)
=14/24
=7/12
Therefore our answer is 7/12

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4 years ago

A shop sells chocolate, vanilla and strawberry ice creams. 45% of the ice creams sold are vanilla, and 1/4 are strawberry. What

Alinara [238K]

Answer:

Step-by-step explanation:

Total percentage = 100%

And we know that proportions of Vanilla +chocolate +strawberry = 100%

Proportion of Vanilla = 45%

Proportion of Strawberry = 1/4 *100 = 25%

Let proportion of chocolate be represented by variable C;

So, 45% +25% + C = 100%

65% +C = 100%

Subtract 65% from both sides to solve for C;

C=100% - 65%

C = 35%

Therefore there is 35% of chocolate in the shop.

8 0

3 years ago

6.1 is 1/3 of what? Please help ASAP!

murzikaleks [220]

Answer:

Step-by-step explanation:

Round 6.1 down to 6. If you divide 18 by 3 you get 6.

Therefore, 6 is one third of 18.

6 0

3 years ago

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What is the y-intercept? (20,0) 0 (0, 18) (18,0) O (0,20)

Y_Kistochka [10]

The answer is (0,18)

4 0

3 years ago

Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D

Ivahew [28]

Check the picture below.

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D$

$\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D$

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3 years ago