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kobusy [5.1K]
3 years ago
8

Determine the zeros of the function f(x) = 3x2 – 7x + 1. x = StartFraction 7 plus or minus StartRoot 37 EndRoot Over 6 EndFracti

on x = StartFraction negative 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction x = StartFraction 7 plus or minus StartRoot 61 EndRoot Over 6 EndFraction x = StartFraction negative 7 plus or minus StartRoot 61 EndRoot Over 6 EndFraction
Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer: the answer is option A. or x = StartFraction 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction

Step-by-step explanation:got it right on edge

Ksivusya [100]3 years ago
3 0

Answer:

x = 7| 37

_______

     6

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If a recipe calls for 0.800 kg of flour , about how many ounces of flour does it need? (1lb=16 oz, 1 lb = 0.454 kg )
stiks02 [169]
For this case we must take into account the following conversions of units:
 1lb = 16 oz
 1 lb = 0.454 kg
 Applying the conversion of units we have:
 (0.800) * (1 / 0.454) * (16/1) = 28.1938326
 Rounding off we have:
 28.2 oz
 Answer:
 
it needs 28.2 oz of flour
8 0
3 years ago
Read 2 more answers
Solve the following equation for a: -g + 3/4a = y
matrenka [14]

9514 1404 393

Answer:

  a = (4/3)(y+g)

Step-by-step explanation:

Isolate 'a' term, then multiply by the reciprocal of its coefficient.

  -g+\dfrac{3}{4}a=y\qquad\text{given}\\\\\dfrac{3}{4}a=y+g\qquad\text{add $g$}\\\\\boxed{a=\dfrac{4(y+g)}{3}}\qquad\text{multiply by $4/3$}

4 0
3 years ago
10x + 60 = 9x - 30<br><img src="https://tex.z-dn.net/?f=10x%20%2B%2060%20%3D%209%20%5Ctimes%20%20-%2030%20%5C%5C%20" id="TexForm
EastWind [94]

Answer:

x = - 90

Step-by-step explanation:

Given

10x + 60 = 9x - 30 ( subtract 9x from both sides )

x + 60 = - 30 ( subtract 60 from both sides )

x = - 90

4 0
3 years ago
Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
Will give brainliest
Snezhnost [94]
I believe it's the first option. Hope this helps.
3 0
3 years ago
Read 2 more answers
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